1422410434117 has 2 divisors, whose sum is σ = 1422410434118. Its totient is φ = 1422410434116.

The previous prime is 1422410434063. The next prime is 1422410434171. The reversal of 1422410434117 is 7114340142241.

Together with next prime (1422410434171) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1422410434063) and next prime (1422410434171).

It can be written as a sum of positive squares in only one way, i.e., 1020360596641 + 402049837476 = 1010129^2 + 634074^2 .

It is a cyclic number.

It is not a de Polignac number, because 1422410434117 - 2²³ = 1422402045509 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1422420434117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711205217058 + 711205217059.

It is an arithmetic number, because the mean of its divisors is an integer number (711205217059).

Almost surely, 2^{1422410434117} is an apocalyptic number.

It is an amenable number.

1422410434117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1422410434117 is an equidigital number, since it uses as much as digits as its factorization.

1422410434117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 34.

Adding to 1422410434117 its reverse (7114340142241), we get a palindrome (8536750576358).

The spelling of 1422410434117 in words is "one trillion, four hundred twenty-two billion, four hundred ten million, four hundred thirty-four thousand, one hundred seventeen".