Base | Representation |
---|---|
bin | 11010011111111100… |
… | …11101010101011011 |
3 | 1100201110222222021012 |
4 | 31033332131111123 |
5 | 213114012100120 |
6 | 10311411004135 |
7 | 1012356512456 |
oct | 151776352533 |
9 | 40643888235 |
10 | 14226675035 |
11 | 6040650581 |
12 | 291059964b |
13 | 1459575911 |
14 | 98d64049d |
15 | 583eab1c5 |
hex | 34ff9d55b |
14226675035 has 4 divisors (see below), whose sum is σ = 17072010048. Its totient is φ = 11381340024.
The previous prime is 14226675019. The next prime is 14226675053. The reversal of 14226675035 is 53057662241.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14226675035 - 24 = 14226675019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14226674983 and 14226675001.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1422667499 + ... + 1422667508.
It is an arithmetic number, because the mean of its divisors is an integer number (4268002512).
Almost surely, 214226675035 is an apocalyptic number.
14226675035 is a deficient number, since it is larger than the sum of its proper divisors (2845335013).
14226675035 is an equidigital number, since it uses as much as digits as its factorization.
14226675035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2845335012.
The product of its (nonzero) digits is 302400, while the sum is 41.
The spelling of 14226675035 in words is "fourteen billion, two hundred twenty-six million, six hundred seventy-five thousand, thirty-five".
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