Base | Representation |
---|---|
bin | 100000010110101111001110… |
… | …110100101011100101110011 |
3 | 200122211202020212002201102201 |
4 | 200112233032310223211303 |
5 | 122122420431014302212 |
6 | 1222351422034124031 |
7 | 41654560301436544 |
oct | 4026571664534563 |
9 | 618752225081381 |
10 | 142300031400307 |
11 | 41383116a758a0 |
12 | 13b62848720617 |
13 | 6152ab2448b21 |
14 | 271d5031344cb |
15 | 116b83c7cbb57 |
hex | 816bced2b973 |
142300031400307 has 32 divisors (see below), whose sum is σ = 165331181562624. Its totient is φ = 121042254796800.
The previous prime is 142300031400269. The next prime is 142300031400313. The reversal of 142300031400307 is 703004130003241.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142300031400307 is a prime.
It is not an unprimeable number, because it can be changed into a prime (142300031400337) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 23764788 + ... + 29143870.
It is an arithmetic number, because the mean of its divisors is an integer number (5166599423832).
Almost surely, 2142300031400307 is an apocalyptic number.
142300031400307 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
142300031400307 is a deficient number, since it is larger than the sum of its proper divisors (23031150162317).
142300031400307 is a wasteful number, since it uses less digits than its factorization.
142300031400307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5379939.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 142300031400307 its reverse (703004130003241), we get a palindrome (845304161403548).
The spelling of 142300031400307 in words is "one hundred forty-two trillion, three hundred billion, thirty-one million, four hundred thousand, three hundred seven".
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