Base | Representation |
---|---|
bin | 1100111100010011000001… |
… | …1111100100001000111111 |
3 | 1212101101012222012120021001 |
4 | 3033010300133210020333 |
5 | 3331121110244420021 |
6 | 50133105031351131 |
7 | 2666041443150265 |
oct | 317046037441077 |
9 | 55341188176231 |
10 | 14230040232511 |
11 | 4596a2080a124 |
12 | 1719a638224a7 |
13 | 7c2b6ba8381c |
14 | 372a4806c435 |
15 | 19a251797091 |
hex | cf1307e423f |
14230040232511 has 2 divisors, whose sum is σ = 14230040232512. Its totient is φ = 14230040232510.
The previous prime is 14230040232487. The next prime is 14230040232553. The reversal of 14230040232511 is 11523204003241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14230040232511 - 27 = 14230040232383 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 14230040232511.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14230040232211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115020116255 + 7115020116256.
It is an arithmetic number, because the mean of its divisors is an integer number (7115020116256).
Almost surely, 214230040232511 is an apocalyptic number.
14230040232511 is a deficient number, since it is larger than the sum of its proper divisors (1).
14230040232511 is an equidigital number, since it uses as much as digits as its factorization.
14230040232511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5760, while the sum is 28.
Adding to 14230040232511 its reverse (11523204003241), we get a palindrome (25753244235752).
The spelling of 14230040232511 in words is "fourteen trillion, two hundred thirty billion, forty million, two hundred thirty-two thousand, five hundred eleven".
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