Base | Representation |
---|---|
bin | 1100111100010011000010… |
… | …0110101111010000010111 |
3 | 1212101101020002202002212112 |
4 | 3033010300212233100113 |
5 | 3331121111240104142 |
6 | 50133105135541235 |
7 | 2666041465142015 |
oct | 317046046572027 |
9 | 55341202662775 |
10 | 14230042113047 |
11 | 4596a21883a92 |
12 | 1719a6438a81b |
13 | 7c2b6c291777 |
14 | 372a483db8b5 |
15 | 19a251a19382 |
hex | cf1309af417 |
14230042113047 has 2 divisors, whose sum is σ = 14230042113048. Its totient is φ = 14230042113046.
The previous prime is 14230042113013. The next prime is 14230042113101. The reversal of 14230042113047 is 74031124003241.
14230042113047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14230042113047 - 210 = 14230042112023 is a prime.
It is a super-2 number, since 2×142300421130472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14230042113247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115021056523 + 7115021056524.
It is an arithmetic number, because the mean of its divisors is an integer number (7115021056524).
Almost surely, 214230042113047 is an apocalyptic number.
14230042113047 is a deficient number, since it is larger than the sum of its proper divisors (1).
14230042113047 is an equidigital number, since it uses as much as digits as its factorization.
14230042113047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 14230042113047 its reverse (74031124003241), we get a palindrome (88261166116288).
The spelling of 14230042113047 in words is "fourteen trillion, two hundred thirty billion, forty-two million, one hundred thirteen thousand, forty-seven".
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