Base | Representation |
---|---|
bin | 1100111100010011000111… |
… | …0100001001000110101101 |
3 | 1212101101021111220222211210 |
4 | 3033010301310021012231 |
5 | 3331121131433412023 |
6 | 50133111142505033 |
7 | 2666042132462241 |
oct | 317046164110655 |
9 | 55341244828753 |
10 | 14230062404013 |
11 | 4596a32282985 |
12 | 1719a6b135179 |
13 | 7c2b73547461 |
14 | 372a4ada0421 |
15 | 19a2536c6593 |
hex | cf131d091ad |
14230062404013 has 4 divisors (see below), whose sum is σ = 18973416538688. Its totient is φ = 9486708269340.
The previous prime is 14230062404009. The next prime is 14230062404023. The reversal of 14230062404013 is 31040426003241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 14230062404013 - 22 = 14230062404009 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14230062404023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2371677067333 + ... + 2371677067338.
It is an arithmetic number, because the mean of its divisors is an integer number (4743354134672).
Almost surely, 214230062404013 is an apocalyptic number.
It is an amenable number.
14230062404013 is a deficient number, since it is larger than the sum of its proper divisors (4743354134675).
14230062404013 is an equidigital number, since it uses as much as digits as its factorization.
14230062404013 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4743354134674.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 14230062404013 its reverse (31040426003241), we get a palindrome (45270488407254).
The spelling of 14230062404013 in words is "fourteen trillion, two hundred thirty billion, sixty-two million, four hundred four thousand, thirteen".
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