142312211211413 has 4 divisors (see below), whose sum is σ = 143911224820620. Its totient is φ = 140713197602208.

The previous prime is 142312211211377. The next prime is 142312211211481. The reversal of 142312211211413 is 314112112213241.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10804480758289 + 131507730453124 = 3287017^2 + 11467682^2 .

It is a cyclic number.

It is not a de Polignac number, because 142312211211413 - 2⁶ = 142312211211349 is a prime.

It is a super-3 number, since 3×142312211211413³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (142312211271413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 799506804470 + ... + 799506804647.

It is an arithmetic number, because the mean of its divisors is an integer number (35977806205155).

Almost surely, 2^{142312211211413} is an apocalyptic number.

It is an amenable number.

142312211211413 is a deficient number, since it is larger than the sum of its proper divisors (1599013609207).

142312211211413 is an equidigital number, since it uses as much as digits as its factorization.

142312211211413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1599013609206.

The product of its digits is 2304, while the sum is 29.

Adding to 142312211211413 its reverse (314112112213241), we get a palindrome (456424323424654).

The spelling of 142312211211413 in words is "one hundred forty-two trillion, three hundred twelve billion, two hundred eleven million, two hundred eleven thousand, four hundred thirteen".