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14231512879 is a prime number
BaseRepresentation
bin11010100000100001…
…11010011100101111
31100201211002202112121
431100100322130233
5213121231403004
610312102413411
71012445602123
oct152020723457
940654082477
1014231512879
1160433552a1
122912131267
13145a57a94c
1499013d583
15584614854
hex35043a72f

14231512879 has 2 divisors, whose sum is σ = 14231512880. Its totient is φ = 14231512878.

The previous prime is 14231512873. The next prime is 14231512927. The reversal of 14231512879 is 97821513241.

14231512879 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14231512879 - 25 = 14231512847 is a prime.

It is a super-3 number, since 3×142315128793 (a number of 31 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14231512873) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7115756439 + 7115756440.

It is an arithmetic number, because the mean of its divisors is an integer number (7115756440).

Almost surely, 214231512879 is an apocalyptic number.

14231512879 is a deficient number, since it is larger than the sum of its proper divisors (1).

14231512879 is an equidigital number, since it uses as much as digits as its factorization.

14231512879 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120960, while the sum is 43.

The spelling of 14231512879 in words is "fourteen billion, two hundred thirty-one million, five hundred twelve thousand, eight hundred seventy-nine".