142323335441435 has 4 divisors (see below), whose sum is σ = 170788002529728. Its totient is φ = 113858668353144.

The previous prime is 142323335441411. The next prime is 142323335441501. The reversal of 142323335441435 is 534144533323241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142323335441435 - 2²⁰ = 142323334392859 is a prime.

It is a super-3 number, since 3×142323335441435³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 142323335441435.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14232333544139 + ... + 14232333544148.

It is an arithmetic number, because the mean of its divisors is an integer number (42697000632432).

Almost surely, 2^{142323335441435} is an apocalyptic number.

142323335441435 is a deficient number, since it is larger than the sum of its proper divisors (28464667088293).

142323335441435 is an equidigital number, since it uses as much as digits as its factorization.

142323335441435 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28464667088292.

The product of its digits is 6220800, while the sum is 47.

Adding to 142323335441435 its reverse (534144533323241), we get a palindrome (676467868764676).

The spelling of 142323335441435 in words is "one hundred forty-two trillion, three hundred twenty-three billion, three hundred thirty-five million, four hundred forty-one thousand, four hundred thirty-five".