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14232361978453 is a prime number
BaseRepresentation
bin1100111100011011101011…
…1000010100101001010101
31212101121012202222110221111
43033012322320110221111
53331140334131302303
650134131250415021
72666153124522013
oct317067270245125
955347182873844
1014232361978453
114597a02333223
12171a3b1291471
137c314baa09a8
14372bc855b8b3
1519a33a511b6d
hexcf1bae14a55

14232361978453 has 2 divisors, whose sum is σ = 14232361978454. Its totient is φ = 14232361978452.

The previous prime is 14232361978363. The next prime is 14232361978477. The reversal of 14232361978453 is 35487916323241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12993018603889 + 1239343374564 = 3604583^2 + 1113258^2 .

It is a cyclic number.

It is not a de Polignac number, because 14232361978453 - 217 = 14232361847381 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14232361978253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116180989226 + 7116180989227.

It is an arithmetic number, because the mean of its divisors is an integer number (7116180989227).

Almost surely, 214232361978453 is an apocalyptic number.

It is an amenable number.

14232361978453 is a deficient number, since it is larger than the sum of its proper divisors (1).

14232361978453 is an equidigital number, since it uses as much as digits as its factorization.

14232361978453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 26127360, while the sum is 58.

The spelling of 14232361978453 in words is "fourteen trillion, two hundred thirty-two billion, three hundred sixty-one million, nine hundred seventy-eight thousand, four hundred fifty-three".