Base | Representation |
---|---|
bin | 1100111100011110001011… |
… | …0000100011101000001111 |
3 | 1212101122221101220212220222 |
4 | 3033013202300203220033 |
5 | 3331143221421000221 |
6 | 50134321510501555 |
7 | 2666205530421311 |
oct | 317074260435017 |
9 | 55348841825828 |
10 | 14233031031311 |
11 | 4598215a65574 |
12 | 171a5593648bb |
13 | 7c3227595c61 |
14 | 372c4d35b7b1 |
15 | 19a37911e9ab |
hex | cf1e2c23a0f |
14233031031311 has 2 divisors, whose sum is σ = 14233031031312. Its totient is φ = 14233031031310.
The previous prime is 14233031031257. The next prime is 14233031031403. The reversal of 14233031031311 is 11313013033241.
It is a happy number.
14233031031311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (11313013033241) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14233031031311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14233031031811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7116515515655 + 7116515515656.
It is an arithmetic number, because the mean of its divisors is an integer number (7116515515656).
Almost surely, 214233031031311 is an apocalyptic number.
14233031031311 is a deficient number, since it is larger than the sum of its proper divisors (1).
14233031031311 is an equidigital number, since it uses as much as digits as its factorization.
14233031031311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 14233031031311 its reverse (11313013033241), we get a palindrome (25546044064552).
The spelling of 14233031031311 in words is "fourteen trillion, two hundred thirty-three billion, thirty-one million, thirty-one thousand, three hundred eleven".
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