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142330433134 = 2119359652319
BaseRepresentation
bin1000010010001110001…
…1100000111001101110
3111121101020211011000111
42010203203200321232
54312443042330014
6145215151050234
713166036502001
oct2044343407156
9447336734014
10142330433134
11553a890103a
122370221097a
1310563631306
146c62d3d538
153a806052c4
hex21238e0e6e

142330433134 has 8 divisors (see below), whose sum is σ = 213674610240. Its totient is φ = 71105563056.

The previous prime is 142330433111. The next prime is 142330433143. The reversal of 142330433134 is 431334033241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1423304331342 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 142330433096 and 142330433105.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29823774 + ... + 29828545.

It is an arithmetic number, because the mean of its divisors is an integer number (26709326280).

Almost surely, 2142330433134 is an apocalyptic number.

142330433134 is a deficient number, since it is larger than the sum of its proper divisors (71344177106).

142330433134 is a wasteful number, since it uses less digits than its factorization.

142330433134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 59653514.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 142330433134 its reverse (431334033241), we get a palindrome (573664466375).

The spelling of 142330433134 in words is "one hundred forty-two billion, three hundred thirty million, four hundred thirty-three thousand, one hundred thirty-four".

Divisors: 1 2 1193 2386 59652319 119304638 71165216567 142330433134