Base | Representation |
---|---|
bin | 10100101101100100101… |
… | …010010111110011001111 |
3 | 12001001211211100011101221 |
4 | 110231210222113303033 |
5 | 141304431142112421 |
6 | 3005510543344211 |
7 | 204555161626411 |
oct | 24554452276317 |
9 | 5031754304357 |
10 | 1423323004111 |
11 | 4a969a8034a8 |
12 | 1aba23bb2067 |
13 | a42ac889718 |
14 | 4cc63d789b1 |
15 | 270559c4841 |
hex | 14b64a97ccf |
1423323004111 has 2 divisors, whose sum is σ = 1423323004112. Its totient is φ = 1423323004110.
The previous prime is 1423323004099. The next prime is 1423323004133. The reversal of 1423323004111 is 1114003233241.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1423323004111 - 225 = 1423289449679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1423323004151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 711661502055 + 711661502056.
It is an arithmetic number, because the mean of its divisors is an integer number (711661502056).
Almost surely, 21423323004111 is an apocalyptic number.
1423323004111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1423323004111 is an equidigital number, since it uses as much as digits as its factorization.
1423323004111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1423323004111 its reverse (1114003233241), we get a palindrome (2537326237352).
The spelling of 1423323004111 in words is "one trillion, four hundred twenty-three billion, three hundred twenty-three million, four thousand, one hundred eleven".
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