Base | Representation |
---|---|
bin | 1100111100011110111101… |
… | …1110001111000100111110 |
3 | 1212101200111021021200221110 |
4 | 3033013233132033010332 |
5 | 3331144141022113400 |
6 | 50134355010342450 |
7 | 2666214030434241 |
oct | 317075736170476 |
9 | 55350437250843 |
10 | 14233244332350 |
11 | 459831540281a |
12 | 171a5b888aa26 |
13 | 7c325c8294a4 |
14 | 372c6d803258 |
15 | 19a38cc04e50 |
hex | cf1ef78f13e |
14233244332350 has 96 divisors (see below), whose sum is σ = 35410337879040. Its totient is φ = 3783516992640.
The previous prime is 14233244332339. The next prime is 14233244332379. The reversal of 14233244332350 is 5323344233241.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14233244332299 and 14233244332308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 69138871 + ... + 69344429.
It is an arithmetic number, because the mean of its divisors is an integer number (368857686240).
Almost surely, 214233244332350 is an apocalyptic number.
14233244332350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14233244332350 is an abundant number, since it is smaller than the sum of its proper divisors (21177093546690).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14233244332350 is a wasteful number, since it uses less digits than its factorization.
14233244332350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207034 (or 207029 counting only the distinct ones).
The product of its (nonzero) digits is 622080, while the sum is 39.
Adding to 14233244332350 its reverse (5323344233241), we get a palindrome (19556588565591).
The spelling of 14233244332350 in words is "fourteen trillion, two hundred thirty-three billion, two hundred forty-four million, three hundred thirty-two thousand, three hundred fifty".
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