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1423421220124 = 221269612802871
BaseRepresentation
bin10100101101101010100…
…001000010010100011100
312001002002200011001110001
4110231222201002110130
5141310131313020444
63005524412424044
7204560463511441
oct24555241022434
95032080131401
101423421220124
114a9740196662
121aba50a78024
13a42c70271c7
144cc730239c8
152705e4258d4
hex14b6a84251c

1423421220124 has 12 divisors (see below), whose sum is σ = 2491007644048. Its totient is φ = 711704750400.

The previous prime is 1423421220113. The next prime is 1423421220149. The reversal of 1423421220124 is 4210221243241.

It is a super-2 number, since 2×14234212201242 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1423421220092 and 1423421220101.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 893592 + ... + 1909279.

Almost surely, 21423421220124 is an apocalyptic number.

It is an amenable number.

1423421220124 is a deficient number, since it is larger than the sum of its proper divisors (1067586423924).

1423421220124 is a wasteful number, since it uses less digits than its factorization.

1423421220124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2929836 (or 2929834 counting only the distinct ones).

The product of its (nonzero) digits is 6144, while the sum is 28.

Adding to 1423421220124 its reverse (4210221243241), we get a palindrome (5633642463365).

The spelling of 1423421220124 in words is "one trillion, four hundred twenty-three billion, four hundred twenty-one million, two hundred twenty thousand, one hundred twenty-four".

Divisors: 1 2 4 126961 253922 507844 2802871 5605742 11211484 355855305031 711710610062 1423421220124