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14235114741 = 34745038247
BaseRepresentation
bin11010100000111101…
…01001110011110101
31100202001212202100220
431100132221303311
5213123142132431
610312311524553
71012521323151
oct152036516365
940661782326
1014235114741
116045395441
122913389759
13145b23c223
149907da061
15584ac6b96
hex3507a9cf5

14235114741 has 4 divisors (see below), whose sum is σ = 18980152992. Its totient is φ = 9490076492.

The previous prime is 14235114737. The next prime is 14235114769. The reversal of 14235114741 is 14741153241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14235114741 - 22 = 14235114737 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14235116741) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2372519121 + ... + 2372519126.

It is an arithmetic number, because the mean of its divisors is an integer number (4745038248).

Almost surely, 214235114741 is an apocalyptic number.

It is an amenable number.

14235114741 is a deficient number, since it is larger than the sum of its proper divisors (4745038251).

14235114741 is an equidigital number, since it uses as much as digits as its factorization.

14235114741 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4745038250.

The product of its digits is 13440, while the sum is 33.

Adding to 14235114741 its reverse (14741153241), we get a palindrome (28976267982).

The spelling of 14235114741 in words is "fourteen billion, two hundred thirty-five million, one hundred fourteen thousand, seven hundred forty-one".

Divisors: 1 3 4745038247 14235114741