14241000121133 has 2 divisors, whose sum is σ = 14241000121134. Its totient is φ = 14241000121132.

The previous prime is 14241000121093. The next prime is 14241000121157. The reversal of 14241000121133 is 33112100014241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12297772485124 + 1943227636009 = 3506818^2 + 1393997^2 .

It is a cyclic number.

It is not a de Polignac number, because 14241000121133 - 2⁶ = 14241000121069 is a prime.

It is a super-2 number, since 2×14241000121133² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14241000121099 and 14241000121108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14241000121333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7120500060566 + 7120500060567.

It is an arithmetic number, because the mean of its divisors is an integer number (7120500060567).

Almost surely, 2^{14241000121133} is an apocalyptic number.

It is an amenable number.

14241000121133 is a deficient number, since it is larger than the sum of its proper divisors (1).

14241000121133 is an equidigital number, since it uses as much as digits as its factorization.

14241000121133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 14241000121133 its reverse (33112100014241), we get a palindrome (47353100135374).

The spelling of 14241000121133 in words is "fourteen trillion, two hundred forty-one billion, one hundred twenty-one thousand, one hundred thirty-three".