Base | Representation |
---|---|
bin | 1100111101000000000010… |
… | …1111111110110100000111 |
3 | 1212102112102010012020111211 |
4 | 3033100000233332310013 |
5 | 3331320332234202331 |
6 | 50142424055312251 |
7 | 2666650053456616 |
oct | 317200057766407 |
9 | 55375363166454 |
10 | 14242124131591 |
11 | 45a1061865384 |
12 | 172027667b687 |
13 | 7c4046412375 |
14 | 373472c8987d |
15 | 19a70c58b8b1 |
hex | cf400bfed07 |
14242124131591 has 2 divisors, whose sum is σ = 14242124131592. Its totient is φ = 14242124131590.
The previous prime is 14242124131409. The next prime is 14242124131603. The reversal of 14242124131591 is 19513142124241.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14242124131591 - 219 = 14242123607303 is a prime.
It is a super-3 number, since 3×142421241315913 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14242124101591) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7121062065795 + 7121062065796.
It is an arithmetic number, because the mean of its divisors is an integer number (7121062065796).
Almost surely, 214242124131591 is an apocalyptic number.
14242124131591 is a deficient number, since it is larger than the sum of its proper divisors (1).
14242124131591 is an equidigital number, since it uses as much as digits as its factorization.
14242124131591 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 69120, while the sum is 40.
The spelling of 14242124131591 in words is "fourteen trillion, two hundred forty-two billion, one hundred twenty-four million, one hundred thirty-one thousand, five hundred ninety-one".
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