Base | Representation |
---|---|
bin | 1000010010100011111… |
… | …0010001100101000111 |
3 | 111121121120212102000221 |
4 | 2010220332101211013 |
5 | 4313134330144333 |
6 | 145232155245211 |
7 | 13201222240051 |
oct | 2045076214507 |
9 | 447546772027 |
10 | 142421334343 |
11 | 55445148502 |
12 | 23728749807 |
13 | 1057940a502 |
14 | 6c710428d1 |
15 | 3a885add2d |
hex | 2128f91947 |
142421334343 has 2 divisors, whose sum is σ = 142421334344. Its totient is φ = 142421334342.
The previous prime is 142421334317. The next prime is 142421334347. The reversal of 142421334343 is 343433124241.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-142421334343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 142421334299 and 142421334308.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (142421334347) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71210667171 + 71210667172.
It is an arithmetic number, because the mean of its divisors is an integer number (71210667172).
Almost surely, 2142421334343 is an apocalyptic number.
142421334343 is a deficient number, since it is larger than the sum of its proper divisors (1).
142421334343 is an equidigital number, since it uses as much as digits as its factorization.
142421334343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 34.
Adding to 142421334343 its reverse (343433124241), we get a palindrome (485854458584).
The spelling of 142421334343 in words is "one hundred forty-two billion, four hundred twenty-one million, three hundred thirty-four thousand, three hundred forty-three".
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