Base | Representation |
---|---|
bin | 100000011000100001000010… |
… | …101001010010001101010110 |
3 | 200200021102200100012102012112 |
4 | 200120201002221102031112 |
5 | 122131421213303412402 |
6 | 1222523512040351022 |
7 | 41666444501446133 |
oct | 4030410251221526 |
9 | 620242610172175 |
10 | 142422233654102 |
11 | 4141aa25a59876 |
12 | 13b82471a75472 |
13 | 616148897363c |
14 | 27253b6b4358a |
15 | 116eae0c96e52 |
hex | 818842a52356 |
142422233654102 has 4 divisors (see below), whose sum is σ = 213633350481156. Its totient is φ = 71211116827050.
The previous prime is 142422233654089. The next prime is 142422233654119. The reversal of 142422233654102 is 201456332224241.
It is a semiprime because it is the product of two primes.
It is a self number, because there is not a number n which added to its sum of digits gives 142422233654102.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35605558413524 + ... + 35605558413527.
It is an arithmetic number, because the mean of its divisors is an integer number (53408337620289).
Almost surely, 2142422233654102 is an apocalyptic number.
142422233654102 is a deficient number, since it is larger than the sum of its proper divisors (71211116827054).
142422233654102 is an equidigital number, since it uses as much as digits as its factorization.
142422233654102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71211116827053.
The product of its (nonzero) digits is 552960, while the sum is 41.
Adding to 142422233654102 its reverse (201456332224241), we get a palindrome (343878565878343).
The spelling of 142422233654102 in words is "one hundred forty-two trillion, four hundred twenty-two billion, two hundred thirty-three million, six hundred fifty-four thousand, one hundred two".
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