Base | Representation |
---|---|
bin | 100000011000101011100011… |
… | …100011001001110110111100 |
3 | 200200022111211010022100221211 |
4 | 200120223203203021312330 |
5 | 122132112323404112104 |
6 | 1222533020204534204 |
7 | 42000324324330505 |
oct | 4030534343116674 |
9 | 620274733270854 |
10 | 142433523113404 |
11 | 41424799621726 |
12 | 13b846a2851364 |
13 | 6162567848083 |
14 | 2725b68241bac |
15 | 1170051e61e04 |
hex | 818ae38c9dbc |
142433523113404 has 12 divisors (see below), whose sum is σ = 249289671682800. Its totient is φ = 71207902632608.
The previous prime is 142433523113393. The next prime is 142433523113467. The reversal of 142433523113404 is 404311325334241.
142433523113404 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2214694849 + ... + 2214759160.
It is an arithmetic number, because the mean of its divisors is an integer number (20774139306900).
Almost surely, 2142433523113404 is an apocalyptic number.
It is an amenable number.
142433523113404 is a deficient number, since it is larger than the sum of its proper divisors (106856148569396).
142433523113404 is a wasteful number, since it uses less digits than its factorization.
142433523113404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4429462052 (or 4429462050 counting only the distinct ones).
The product of its (nonzero) digits is 414720, while the sum is 40.
Adding to 142433523113404 its reverse (404311325334241), we get a palindrome (546744848447645).
The spelling of 142433523113404 in words is "one hundred forty-two trillion, four hundred thirty-three billion, five hundred twenty-three million, one hundred thirteen thousand, four hundred four".
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