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14244221335 = 53776995791
BaseRepresentation
bin11010100010000010…
…11001000110010111
31100202201000102021011
431101001121012113
5213133010040320
610313235033051
71012661612041
oct152101310627
940681012234
1014244221335
11604a545353
12291643b787
1314600aa246
14991acaa91
155857c505a
hex351059197

14244221335 has 8 divisors (see below), whose sum is σ = 17555040576. Its totient is φ = 11087393760.

The previous prime is 14244221317. The next prime is 14244221339. The reversal of 14244221335 is 53312244241.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-14244221335 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14244221297 and 14244221306.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14244221339) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38497711 + ... + 38498080.

It is an arithmetic number, because the mean of its divisors is an integer number (2194380072).

Almost surely, 214244221335 is an apocalyptic number.

14244221335 is a deficient number, since it is larger than the sum of its proper divisors (3310819241).

14244221335 is an equidigital number, since it uses as much as digits as its factorization.

14244221335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76995833.

The product of its digits is 23040, while the sum is 31.

Adding to 14244221335 its reverse (53312244241), we get a palindrome (67556465576).

The spelling of 14244221335 in words is "fourteen billion, two hundred forty-four million, two hundred twenty-one thousand, three hundred thirty-five".

Divisors: 1 5 37 185 76995791 384978955 2848844267 14244221335