142442315130001 has 4 divisors (see below), whose sum is σ = 148635459266112. Its totient is φ = 136249170993892.

The previous prime is 142442315129969. The next prime is 142442315130043. The reversal of 142442315130001 is 100031513244241.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142442315130001 - 2⁵ = 142442315129969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (142442315130301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3096572068021 + ... + 3096572068066.

It is an arithmetic number, because the mean of its divisors is an integer number (37158864816528).

Almost surely, 2^{142442315130001} is an apocalyptic number.

It is an amenable number.

142442315130001 is a deficient number, since it is larger than the sum of its proper divisors (6193144136111).

142442315130001 is an equidigital number, since it uses as much as digits as its factorization.

142442315130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6193144136110.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 142442315130001 its reverse (100031513244241), we get a palindrome (242473828374242).

The spelling of 142442315130001 in words is "one hundred forty-two trillion, four hundred forty-two billion, three hundred fifteen million, one hundred thirty thousand, one".