14245214503 has 4 divisors (see below), whose sum is σ = 15341000248. Its totient is φ = 13149428760.

The previous prime is 14245214491. The next prime is 14245214507. The reversal of 14245214503 is 30541254241.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14245214503 - 2⁵ = 14245214471 is a prime.

It is a super-2 number, since 2×14245214503² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14245214507) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 547892853 + ... + 547892878.

It is an arithmetic number, because the mean of its divisors is an integer number (3835250062).

Almost surely, 2^14245214503 is an apocalyptic number.

14245214503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14245214503 is a deficient number, since it is larger than the sum of its proper divisors (1095785745).

14245214503 is a wasteful number, since it uses less digits than its factorization.

14245214503 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1095785744.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 14245214503 its reverse (30541254241), we get a palindrome (44786468744).

The spelling of 14245214503 in words is "fourteen billion, two hundred forty-five million, two hundred fourteen thousand, five hundred three".