142500115 has 4 divisors (see below), whose sum is σ = 171000144. Its totient is φ = 114000088.

The previous prime is 142500109. The next prime is 142500131. The reversal of 142500115 is 511005241.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 142500115 - 2³ = 142500107 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 142500092 and 142500101.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14250007 + ... + 14250016.

It is an arithmetic number, because the mean of its divisors is an integer number (42750036).

Almost surely, 2^142500115 is an apocalyptic number.

142500115 is a deficient number, since it is larger than the sum of its proper divisors (28500029).

142500115 is an equidigital number, since it uses as much as digits as its factorization.

142500115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28500028.

The product of its (nonzero) digits is 200, while the sum is 19.

The square root of 142500115 is about 11937.3412031323. The cubic root of 142500115 is about 522.3221039188.

Adding to 142500115 its reverse (511005241), we get a palindrome (653505356).

The spelling of 142500115 in words is "one hundred forty-two million, five hundred thousand, one hundred fifteen".