Base | Representation |
---|---|
bin | 1100111101100101000010… |
… | …0100011010111111011111 |
3 | 1212110111001002111211211022 |
4 | 3033121100210122333133 |
5 | 3332001201110310101 |
6 | 50151145230114355 |
7 | 3000451110331355 |
oct | 317312044327737 |
9 | 55414032454738 |
10 | 14252053213151 |
11 | 45a5297541306 |
12 | 172218794b9bb |
13 | 7c4c694cbc60 |
14 | 373b3582b7d5 |
15 | 19aade0dba1b |
hex | cf65091afdf |
14252053213151 has 8 divisors (see below), whose sum is σ = 15348394346544. Its totient is φ = 13155716272320.
The previous prime is 14252053213141. The next prime is 14252053213267. The reversal of 14252053213151 is 15131235025241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14252053213151 - 26 = 14252053213087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14252053213141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 12458036 + ... + 13553846.
It is an arithmetic number, because the mean of its divisors is an integer number (1918549293318).
Almost surely, 214252053213151 is an apocalyptic number.
14252053213151 is a deficient number, since it is larger than the sum of its proper divisors (1096341133393).
14252053213151 is a wasteful number, since it uses less digits than its factorization.
14252053213151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2096281.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 14252053213151 its reverse (15131235025241), we get a palindrome (29383288238392).
The spelling of 14252053213151 in words is "fourteen trillion, two hundred fifty-two billion, fifty-three million, two hundred thirteen thousand, one hundred fifty-one".
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