Base | Representation |
---|---|
bin | 1100111101101001000111… |
… | …1101001001000101010011 |
3 | 1212110120212112201011221102 |
4 | 3033122101331021011103 |
5 | 3332010422423244220 |
6 | 50151450134415015 |
7 | 3000520230556121 |
oct | 317322175110523 |
9 | 55416775634842 |
10 | 14253150212435 |
11 | 45a57aa797092 |
12 | 172243320146b |
13 | 7c50b286bb64 |
14 | 373bdb3c8911 |
15 | 19ab5557d775 |
hex | cf691f49153 |
14253150212435 has 16 divisors (see below), whose sum is σ = 17143552988352. Its totient is φ = 11376033552000.
The previous prime is 14253150212401. The next prime is 14253150212437. The reversal of 14253150212435 is 53421205135241.
It is not a de Polignac number, because 14253150212435 - 232 = 14248855245139 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14253150212437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2215010 + ... + 5780360.
It is an arithmetic number, because the mean of its divisors is an integer number (1071472061772).
Almost surely, 214253150212435 is an apocalyptic number.
14253150212435 is a deficient number, since it is larger than the sum of its proper divisors (2890402775917).
14253150212435 is a wasteful number, since it uses less digits than its factorization.
14253150212435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3567214.
The product of its (nonzero) digits is 144000, while the sum is 38.
Adding to 14253150212435 its reverse (53421205135241), we get a palindrome (67674355347676).
The spelling of 14253150212435 in words is "fourteen trillion, two hundred fifty-three billion, one hundred fifty million, two hundred twelve thousand, four hundred thirty-five".
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