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1425512433500 = 22532851024867
BaseRepresentation
bin10100101111100111001…
…010011000011101011100
312001021111102010200220022
4110233213022120131130
5141323422140333000
63010512114411312
7204663345521441
oct24574712303534
95037442120808
101425512433500
114aa613673181
121b0335290b38
13a456b35987c
144cdd0a639c8
1527132d04585
hex14be729875c

1425512433500 has 24 divisors (see below), whose sum is σ = 3113319155856. Its totient is φ = 570204973200.

The previous prime is 1425512433461. The next prime is 1425512433523. The reversal of 1425512433500 is 53342155241.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1425511934 + ... + 1425512933.

It is an arithmetic number, because the mean of its divisors is an integer number (129721631494).

Almost surely, 21425512433500 is an apocalyptic number.

1425512433500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1425512433500 is an abundant number, since it is smaller than the sum of its proper divisors (1687806722356).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1425512433500 is a wasteful number, since it uses less digits than its factorization.

1425512433500 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2851024886 (or 2851024874 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 35.

Adding to 1425512433500 its reverse (53342155241), we get a palindrome (1478854588741).

The spelling of 1425512433500 in words is "one trillion, four hundred twenty-five billion, five hundred twelve million, four hundred thirty-three thousand, five hundred".

Divisors: 1 2 4 5 10 20 25 50 100 125 250 500 2851024867 5702049734 11404099468 14255124335 28510248670 57020497340 71275621675 142551243350 285102486700 356378108375 712756216750 1425512433500