1426099117 has 2 divisors, whose sum is σ = 1426099118. Its totient is φ = 1426099116.

The previous prime is 1426099109. The next prime is 1426099121. The reversal of 1426099117 is 7119906241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1018503396 + 407595721 = 31914^2 + 20189^2 .

It is a cyclic number.

It is not a de Polignac number, because 1426099117 - 2³ = 1426099109 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1426099117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1426099217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 713049558 + 713049559.

It is an arithmetic number, because the mean of its divisors is an integer number (713049559).

Almost surely, 2^1426099117 is an apocalyptic number.

It is an amenable number.

1426099117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1426099117 is an equidigital number, since it uses as much as digits as its factorization.

1426099117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 40.

The square root of 1426099117 is about 37763.7275305286. The cubic root of 1426099117 is about 1125.5978036320.

The spelling of 1426099117 in words is "one billion, four hundred twenty-six million, ninety-nine thousand, one hundred seventeen".