Base | Representation |
---|---|
bin | 1000010011010110001… |
… | …1100011010111010111 |
3 | 111122011022002100002211 |
4 | 2010311203203113113 |
5 | 4314102400324421 |
6 | 145305140014251 |
7 | 13206364451260 |
oct | 2046543432727 |
9 | 448138070084 |
10 | 142632433111 |
11 | 555433210a3 |
12 | 23787391387 |
13 | 105b107c51c |
14 | 6c910b3967 |
15 | 3a9bdab9e1 |
hex | 21358e35d7 |
142632433111 has 4 divisors (see below), whose sum is σ = 163008494992. Its totient is φ = 122256371232.
The previous prime is 142632433103. The next prime is 142632433117. The reversal of 142632433111 is 111334236241.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111334236241 = 23 ⋅4840618967.
It is a cyclic number.
It is not a de Polignac number, because 142632433111 - 23 = 142632433103 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142632433117) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10188030930 + ... + 10188030943.
It is an arithmetic number, because the mean of its divisors is an integer number (40752123748).
Almost surely, 2142632433111 is an apocalyptic number.
142632433111 is a deficient number, since it is larger than the sum of its proper divisors (20376061881).
142632433111 is an equidigital number, since it uses as much as digits as its factorization.
142632433111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20376061880.
The product of its digits is 10368, while the sum is 31.
Adding to 142632433111 its reverse (111334236241), we get a palindrome (253966669352).
The spelling of 142632433111 in words is "one hundred forty-two billion, six hundred thirty-two million, four hundred thirty-three thousand, one hundred eleven".
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