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1428293828413 is a prime number
BaseRepresentation
bin10100110010001100111…
…100100011111100111101
312001112200020211012102201
4110302030330203330331
5141400121210002123
63012052113351501
7205122311140504
oct24621474437475
95045606735381
101428293828413
115008106a3361
121b0990868591
13a48c267158a
144d1b620383b
15272470b65ad
hex14c8cf23f3d

1428293828413 has 2 divisors, whose sum is σ = 1428293828414. Its totient is φ = 1428293828412.

The previous prime is 1428293828347. The next prime is 1428293828417. The reversal of 1428293828413 is 3148283928241.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1057026621924 + 371267206489 = 1028118^2 + 609317^2 .

It is a cyclic number.

It is not a de Polignac number, because 1428293828413 - 233 = 1419703893821 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1428293828417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 714146914206 + 714146914207.

It is an arithmetic number, because the mean of its divisors is an integer number (714146914207).

Almost surely, 21428293828413 is an apocalyptic number.

It is an amenable number.

1428293828413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1428293828413 is an equidigital number, since it uses as much as digits as its factorization.

1428293828413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5308416, while the sum is 55.

The spelling of 1428293828413 in words is "one trillion, four hundred twenty-eight billion, two hundred ninety-three million, eight hundred twenty-eight thousand, four hundred thirteen".