14300223303 has 4 divisors (see below), whose sum is σ = 19066964408. Its totient is φ = 9533482200.

The previous prime is 14300223271. The next prime is 14300223307. The reversal of 14300223303 is 30332200341.

14300223303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30332200341 = 3 ⋅10110733447.

It is not a de Polignac number, because 14300223303 - 2⁵ = 14300223271 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14300223303.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14300223307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2383370548 + ... + 2383370553.

It is an arithmetic number, because the mean of its divisors is an integer number (4766741102).

Almost surely, 2^14300223303 is an apocalyptic number.

14300223303 is a deficient number, since it is larger than the sum of its proper divisors (4766741105).

14300223303 is an equidigital number, since it uses as much as digits as its factorization.

14300223303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4766741104.

The product of its (nonzero) digits is 1296, while the sum is 21.

Adding to 14300223303 its reverse (30332200341), we get a palindrome (44632423644).

The spelling of 14300223303 in words is "fourteen billion, three hundred million, two hundred twenty-three thousand, three hundred three".