Base | Representation |
---|---|
bin | 11010101000101110… |
… | …10110101110101101 |
3 | 1100220121120001001121 |
4 | 31110113112232231 |
5 | 213241334413240 |
6 | 10323001140541 |
7 | 1014242430121 |
oct | 152427265655 |
9 | 40817501047 |
10 | 14300310445 |
11 | 6079174993 |
12 | 293118a751 |
13 | 146b8b8075 |
14 | 99932b581 |
15 | 58a6a404a |
hex | 3545d6bad |
14300310445 has 4 divisors (see below), whose sum is σ = 17160372540. Its totient is φ = 11440248352.
The previous prime is 14300310439. The next prime is 14300310469. The reversal of 14300310445 is 54401300341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 10493543844 + 3806766601 = 102438^2 + 61699^2 .
It is a cyclic number.
It is not a de Polignac number, because 14300310445 - 27 = 14300310317 is a prime.
It is a super-4 number, since 4×143003104454 (a number of 42 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1430031040 + ... + 1430031049.
It is an arithmetic number, because the mean of its divisors is an integer number (4290093135).
Almost surely, 214300310445 is an apocalyptic number.
It is an amenable number.
14300310445 is a deficient number, since it is larger than the sum of its proper divisors (2860062095).
14300310445 is an equidigital number, since it uses as much as digits as its factorization.
14300310445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2860062094.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 14300310445 its reverse (54401300341), we get a palindrome (68701610786).
The spelling of 14300310445 in words is "fourteen billion, three hundred million, three hundred ten thousand, four hundred forty-five".
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