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1430034434111 = 8920316031237
BaseRepresentation
bin10100110011110100101…
…100011100100000111111
312001201011120002010120102
4110303310230130200333
5141412202303342421
63012540532511315
7205213405062623
oct24636454344077
95051146063512
101430034434111
11501524180168
121b119777b53b
13a4b0c16728a
144d2dd459183
15272e9cdb60b
hex14cf4b1c83f

1430034434111 has 4 divisors (see below), whose sum is σ = 1430050554552. Its totient is φ = 1430018313672.

The previous prime is 1430034434107. The next prime is 1430034434131. The reversal of 1430034434111 is 1114344300341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1430034434111 - 22 = 1430034434107 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1430034434131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7926416 + ... + 8104821.

It is an arithmetic number, because the mean of its divisors is an integer number (357512638638).

Almost surely, 21430034434111 is an apocalyptic number.

1430034434111 is a deficient number, since it is larger than the sum of its proper divisors (16120441).

1430034434111 is an equidigital number, since it uses as much as digits as its factorization.

1430034434111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16120440.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1430034434111 its reverse (1114344300341), we get a palindrome (2544378734452).

The spelling of 1430034434111 in words is "one trillion, four hundred thirty billion, thirty-four million, four hundred thirty-four thousand, one hundred eleven".

Divisors: 1 89203 16031237 1430034434111