143004041310421 has 2 divisors, whose sum is σ = 143004041310422. Its totient is φ = 143004041310420.

The previous prime is 143004041310419. The next prime is 143004041310451. The reversal of 143004041310421 is 124013140400341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 142887955280625 + 116086029796 = 11953575^2 + 340714^2 .

It is an emirp because it is prime and its reverse (124013140400341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143004041310421 - 2¹ = 143004041310419 is a prime.

It is a super-2 number, since 2×143004041310421² (a number of 29 digits) contains 22 as substring.

Together with 143004041310419, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 143004041310421.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (143004041310451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71502020655210 + 71502020655211.

It is an arithmetic number, because the mean of its divisors is an integer number (71502020655211).

Almost surely, 2^{143004041310421} is an apocalyptic number.

It is an amenable number.

143004041310421 is a deficient number, since it is larger than the sum of its proper divisors (1).

143004041310421 is an equidigital number, since it uses as much as digits as its factorization.

143004041310421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 143004041310421 its reverse (124013140400341), we get a palindrome (267017181710762).

The spelling of 143004041310421 in words is "one hundred forty-three trillion, four billion, forty-one million, three hundred ten thousand, four hundred twenty-one".