14300413421231 has 4 divisors (see below), whose sum is σ = 16343329624272. Its totient is φ = 12257497218192.

The previous prime is 14300413421207. The next prime is 14300413421237. The reversal of 14300413421231 is 13212431400341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14300413421231 - 2¹⁰ = 14300413420207 is a prime.

It is a super-2 number, since 2×14300413421231² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14300413421194 and 14300413421203.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14300413421237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1021458101510 + ... + 1021458101523.

It is an arithmetic number, because the mean of its divisors is an integer number (4085832406068).

Almost surely, 2^{14300413421231} is an apocalyptic number.

14300413421231 is a deficient number, since it is larger than the sum of its proper divisors (2042916203041).

14300413421231 is an equidigital number, since it uses as much as digits as its factorization.

14300413421231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2042916203040.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14300413421231 its reverse (13212431400341), we get a palindrome (27512844821572).

The spelling of 14300413421231 in words is "fourteen trillion, three hundred billion, four hundred thirteen million, four hundred twenty-one thousand, two hundred thirty-one".