14300538341 has 2 divisors, whose sum is σ = 14300538342. Its totient is φ = 14300538340.

The previous prime is 14300538299. The next prime is 14300538349. The reversal of 14300538341 is 14383500341.

14300538341 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11591752225 + 2708786116 = 107665^2 + 52046^2 .

It is a cyclic number.

It is not a de Polignac number, because 14300538341 - 2²² = 14296344037 is a prime.

It is a super-2 number, since 2×14300538341² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14300538298 and 14300538307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14300538349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7150269170 + 7150269171.

It is an arithmetic number, because the mean of its divisors is an integer number (7150269171).

Almost surely, 2^14300538341 is an apocalyptic number.

It is an amenable number.

14300538341 is a deficient number, since it is larger than the sum of its proper divisors (1).

14300538341 is an equidigital number, since it uses as much as digits as its factorization.

14300538341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

The spelling of 14300538341 in words is "fourteen billion, three hundred million, five hundred thirty-eight thousand, three hundred forty-one".