Base | Representation |
---|---|
bin | 11010101001001110… |
… | …00011000010101111 |
3 | 1100220220022000221121 |
4 | 31110213003002233 |
5 | 213243413032421 |
6 | 10323225241411 |
7 | 1014322412245 |
oct | 152447030257 |
9 | 40826260847 |
10 | 14304424111 |
11 | 608052460a |
12 | 2932633267 |
13 | 146c6c85a3 |
14 | 999abc795 |
15 | 58ac17d41 |
hex | 3549c30af |
14304424111 has 2 divisors, whose sum is σ = 14304424112. Its totient is φ = 14304424110.
The previous prime is 14304424093. The next prime is 14304424117. The reversal of 14304424111 is 11142440341.
14304424111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14304424111 - 227 = 14170206383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14304424117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7152212055 + 7152212056.
It is an arithmetic number, because the mean of its divisors is an integer number (7152212056).
Almost surely, 214304424111 is an apocalyptic number.
14304424111 is a deficient number, since it is larger than the sum of its proper divisors (1).
14304424111 is an equidigital number, since it uses as much as digits as its factorization.
14304424111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 14304424111 its reverse (11142440341), we get a palindrome (25446864452).
The spelling of 14304424111 in words is "fourteen billion, three hundred four million, four hundred twenty-four thousand, one hundred eleven".
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