Base | Representation |
---|---|
bin | 10100110100001110010… |
… | …000100011101010111111 |
3 | 12001202021110010100111122 |
4 | 110310032100203222333 |
5 | 141414042103043012 |
6 | 3013051253341155 |
7 | 205230133460114 |
oct | 24641620435277 |
9 | 5052243110448 |
10 | 1430463331007 |
11 | 501724292807 |
12 | 1b12973377bb |
13 | a4b79c85719 |
14 | 4d3403c290b |
15 | 273227abe72 |
hex | 14d0e423abf |
1430463331007 has 2 divisors, whose sum is σ = 1430463331008. Its totient is φ = 1430463331006.
The previous prime is 1430463330983. The next prime is 1430463331009. The reversal of 1430463331007 is 7001333640341.
It is a strong prime.
It is an emirp because it is prime and its reverse (7001333640341) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1430463331007 is a prime.
Together with 1430463331009, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1430463331009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715231665503 + 715231665504.
It is an arithmetic number, because the mean of its divisors is an integer number (715231665504).
Almost surely, 21430463331007 is an apocalyptic number.
1430463331007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1430463331007 is an equidigital number, since it uses as much as digits as its factorization.
1430463331007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 1430463331007 its reverse (7001333640341), we get a palindrome (8431796971348).
The spelling of 1430463331007 in words is "one trillion, four hundred thirty billion, four hundred sixty-three million, three hundred thirty-one thousand, seven".
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