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14310095340 = 2235238501589
BaseRepresentation
bin11010101001111001…
…01011100111101100
31100221021222011102010
431110330223213230
5213301341022330
610323551001220
71014421542402
oct152474534754
940837864363
1014310095340
116083748482
122934509210
131470932a48
1499a757472
1558b4883b0
hex354f2b9ec

14310095340 has 24 divisors (see below), whose sum is σ = 40068267120. Its totient is φ = 3816025408.

The previous prime is 14310095333. The next prime is 14310095377. The reversal of 14310095340 is 4359001341.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a junction number, because it is equal to n+sod(n) for n = 14310095298 and 14310095307.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 119250735 + ... + 119250854.

It is an arithmetic number, because the mean of its divisors is an integer number (1669511130).

Almost surely, 214310095340 is an apocalyptic number.

14310095340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

14310095340 is an abundant number, since it is smaller than the sum of its proper divisors (25758171780).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14310095340 is a wasteful number, since it uses less digits than its factorization.

14310095340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 238501601 (or 238501599 counting only the distinct ones).

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 14310095340 its reverse (4359001341), we get a palindrome (18669096681).

The spelling of 14310095340 in words is "fourteen billion, three hundred ten million, ninety-five thousand, three hundred forty".

Divisors: 1 2 3 4 5 6 10 12 15 20 30 60 238501589 477003178 715504767 954006356 1192507945 1431009534 2385015890 2862019068 3577523835 4770031780 7155047670 14310095340