14310129991 has 4 divisors (see below), whose sum is σ = 14323295872. Its totient is φ = 14296964112.

The previous prime is 14310129989. The next prime is 14310130033. The reversal of 14310129991 is 19992101341.

14310129991 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 19992101341 = 108947 ⋅183503.

It is a cyclic number.

It is not a de Polignac number, because 14310129991 - 2¹ = 14310129989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14310129391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6581310 + ... + 6583483.

It is an arithmetic number, because the mean of its divisors is an integer number (3580823968).

Almost surely, 2^14310129991 is an apocalyptic number.

14310129991 is a deficient number, since it is larger than the sum of its proper divisors (13165881).

14310129991 is a wasteful number, since it uses less digits than its factorization.

14310129991 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13165880.

The product of its (nonzero) digits is 17496, while the sum is 40.

The spelling of 14310129991 in words is "fourteen billion, three hundred ten million, one hundred twenty-nine thousand, nine hundred ninety-one".