Search a number
-
+
1431034300511 = 8101717663383
BaseRepresentation
bin10100110100110000010…
…010101000100001011111
312001210202020111121102022
4110310300102220201133
5141421224240104021
63013224051250355
7205250235566204
oct24646022504137
95053666447368
101431034300511
11501997612632
121b14165a99bb
13a4c3b3586ba
144d39616dcab
15273579931ab
hex14d304a885f

1431034300511 has 4 divisors (see below), whose sum is σ = 1431052044912. Its totient is φ = 1431016556112.

The previous prime is 1431034300489. The next prime is 1431034300589. The reversal of 1431034300511 is 1150034301341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1431034300511 is a prime.

It is a super-2 number, since 2×14310343005112 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431034380511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8750675 + ... + 8912708.

It is an arithmetic number, because the mean of its divisors is an integer number (357763011228).

Almost surely, 21431034300511 is an apocalyptic number.

1431034300511 is a deficient number, since it is larger than the sum of its proper divisors (17744401).

1431034300511 is an equidigital number, since it uses as much as digits as its factorization.

1431034300511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17744400.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 1431034300511 its reverse (1150034301341), we get a palindrome (2581068601852).

The spelling of 1431034300511 in words is "one trillion, four hundred thirty-one billion, thirty-four million, three hundred thousand, five hundred eleven".

Divisors: 1 81017 17663383 1431034300511