1431040401341 has 4 divisors (see below), whose sum is σ = 1431101003232. Its totient is φ = 1430979799452.

The previous prime is 1431040401331. The next prime is 1431040401361.

It is a happy number.

1431040401341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431040401341 - 2²² = 1431036207037 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1431040401341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431040401331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30265511 + ... + 30312756.

It is an arithmetic number, because the mean of its divisors is an integer number (357775250808).

Almost surely, 2^{1431040401341} is an apocalyptic number.

It is an amenable number.

1431040401341 is a deficient number, since it is larger than the sum of its proper divisors (60601891).

1431040401341 is an equidigital number, since it uses as much as digits as its factorization.

1431040401341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60601890.

The product of its (nonzero) digits is 2304, while the sum is 26.

It can be divided in two parts, 1431040 and 401341, that added together give a palindrome (1832381).

The spelling of 1431040401341 in words is "one trillion, four hundred thirty-one billion, forty million, four hundred one thousand, three hundred forty-one".