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14310421431 = 34770140477
BaseRepresentation
bin11010101001111011…
…11011001110110111
31100221022120201201120
431110331323032313
5213301431441211
610324001555023
71014424401165
oct152475731667
940838521646
1014310421431
116083950479
122934645a73
131470a182b7
1499a800235
1558b4eed06
hex354f7b3b7

14310421431 has 4 divisors (see below), whose sum is σ = 19080561912. Its totient is φ = 9540280952.

The previous prime is 14310421327. The next prime is 14310421459. The reversal of 14310421431 is 13412401341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13412401341 = 34470800447.

It is a cyclic number.

It is not a de Polignac number, because 14310421431 - 213 = 14310413239 is a prime.

It is a super-2 number, since 2×143104214312 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14310421481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385070236 + ... + 2385070241.

It is an arithmetic number, because the mean of its divisors is an integer number (4770140478).

Almost surely, 214310421431 is an apocalyptic number.

14310421431 is a deficient number, since it is larger than the sum of its proper divisors (4770140481).

14310421431 is an equidigital number, since it uses as much as digits as its factorization.

14310421431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4770140480.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 14310421431 its reverse (13412401341), we get a palindrome (27722822772).

The spelling of 14310421431 in words is "fourteen billion, three hundred ten million, four hundred twenty-one thousand, four hundred thirty-one".

Divisors: 1 3 4770140477 14310421431