1431050242541 has 4 divisors (see below), whose sum is σ = 1431082313952. Its totient is φ = 1431018171132.

The previous prime is 1431050242483. The next prime is 1431050242553. The reversal of 1431050242541 is 1452420501341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1431050242541 - 2⁶ = 1431050242477 is a prime.

It is a super-2 number, since 2×1431050242541² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1431050242498 and 1431050242507.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431050242591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15968681 + ... + 16058046.

It is an arithmetic number, because the mean of its divisors is an integer number (357770578488).

Almost surely, 2^{1431050242541} is an apocalyptic number.

It is an amenable number.

1431050242541 is a deficient number, since it is larger than the sum of its proper divisors (32071411).

1431050242541 is an equidigital number, since it uses as much as digits as its factorization.

1431050242541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32071410.

The product of its (nonzero) digits is 19200, while the sum is 32.

Adding to 1431050242541 its reverse (1452420501341), we get a palindrome (2883470743882).

The spelling of 1431050242541 in words is "one trillion, four hundred thirty-one billion, fifty million, two hundred forty-two thousand, five hundred forty-one".