14311101103 has 4 divisors (see below), whose sum is σ = 15411955048. Its totient is φ = 13210247160.

The previous prime is 14311101073. The next prime is 14311101149. The reversal of 14311101103 is 30110111341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14311101103 is a prime.

It is a super-2 number, since 2×14311101103² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14311101173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550426953 + ... + 550426978.

It is an arithmetic number, because the mean of its divisors is an integer number (3852988762).

Almost surely, 2^14311101103 is an apocalyptic number.

14311101103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14311101103 is a deficient number, since it is larger than the sum of its proper divisors (1100853945).

14311101103 is a wasteful number, since it uses less digits than its factorization.

14311101103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1100853944.

The product of its (nonzero) digits is 36, while the sum is 16.

Adding to 14311101103 its reverse (30110111341), we get a palindrome (44421212444).

The spelling of 14311101103 in words is "fourteen billion, three hundred eleven million, one hundred one thousand, one hundred three".