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14311135005 = 35954075667
BaseRepresentation
bin11010101010000001…
…01001011100011101
31100221100220222120020
431111000221130131
5213302122310010
610324025142353
71014433432446
oct152500513435
940840828506
1014311135005
116084298602
12293492a9b9
131470c0802b
1499a9482cd
1558b5e1470
hex35502971d

14311135005 has 8 divisors (see below), whose sum is σ = 22897816032. Its totient is φ = 7632605328.

The previous prime is 14311135001. The next prime is 14311135039. The reversal of 14311135005 is 50053111341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14311135005 - 22 = 14311135001 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14311135001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 477037819 + ... + 477037848.

It is an arithmetic number, because the mean of its divisors is an integer number (2862227004).

Almost surely, 214311135005 is an apocalyptic number.

14311135005 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

14311135005 is a deficient number, since it is larger than the sum of its proper divisors (8586681027).

14311135005 is an equidigital number, since it uses as much as digits as its factorization.

14311135005 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 954075675.

The product of its (nonzero) digits is 900, while the sum is 24.

Adding to 14311135005 its reverse (50053111341), we get a palindrome (64364246346).

The spelling of 14311135005 in words is "fourteen billion, three hundred eleven million, one hundred thirty-five thousand, five".

Divisors: 1 3 5 15 954075667 2862227001 4770378335 14311135005