1431120001 has 2 divisors, whose sum is σ = 1431120002. Its totient is φ = 1431120000.

The previous prime is 1431119999. The next prime is 1431120011. The reversal of 1431120001 is 1000211341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1430730625 + 389376 = 37825^2 + 624^2 .

It is an emirp because it is prime and its reverse (1000211341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1431120001 - 2¹ = 1431119999 is a prime.

Together with 1431119999, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1431120011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 715560000 + 715560001.

It is an arithmetic number, because the mean of its divisors is an integer number (715560001).

Almost surely, 2^1431120001 is an apocalyptic number.

It is an amenable number.

1431120001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1431120001 is an equidigital number, since it uses as much as digits as its factorization.

1431120001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 1431120001 is about 37830.1467218936. The cubic root of 1431120001 is about 1126.9172249000.

Adding to 1431120001 its reverse (1000211341), we get a palindrome (2431331342).

The spelling of 1431120001 in words is "one billion, four hundred thirty-one million, one hundred twenty thousand, one".