Base | Representation |
---|---|
bin | 1000010101001000100… |
… | …1110000101110001101 |
3 | 111200101201212121002220 |
4 | 2011102021300232031 |
5 | 4321043211230331 |
6 | 145424515205553 |
7 | 13224311503521 |
oct | 2052211605615 |
9 | 450351777086 |
10 | 143112211341 |
11 | 5576a126630 |
12 | 2389bba68b9 |
13 | 106595a4278 |
14 | 6cd8ac3d81 |
15 | 3ac907d296 |
hex | 2152270b8d |
143112211341 has 32 divisors (see below), whose sum is σ = 223198156800. Its totient is φ = 80599284480.
The previous prime is 143112211337. The next prime is 143112211343.
143112211341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 143112211341 - 22 = 143112211337 is a prime.
It is a super-2 number, since 2×1431122113412 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143112211343) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1570251 + ... + 1658888.
It is an arithmetic number, because the mean of its divisors is an integer number (6974942400).
Almost surely, 2143112211341 is an apocalyptic number.
143112211341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
143112211341 is a deficient number, since it is larger than the sum of its proper divisors (80085945459).
143112211341 is a wasteful number, since it uses less digits than its factorization.
143112211341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3229249.
The product of its digits is 576, while the sum is 24.
It can be divided in two parts, 143112 and 211341, that added together give a palindrome (354453).
The spelling of 143112211341 in words is "one hundred forty-three billion, one hundred twelve million, two hundred eleven thousand, three hundred forty-one".
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