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14311222103 = 42893336727
BaseRepresentation
bin11010101010000001…
…11110101101010111
31100221101002102001002
431111000332231113
5213302133101403
610324031053515
71014434244413
oct152500765527
940841072032
1014311222103
116084347a92
12293497129b
131470c38879
1499a96bd43
1558b60c188
hex35503eb57

14311222103 has 4 divisors (see below), whose sum is σ = 14314563120. Its totient is φ = 14307881088.

The previous prime is 14311222099. The next prime is 14311222243. The reversal of 14311222103 is 30122211341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14311222103 - 22 = 14311222099 is a prime.

It is a super-2 number, since 2×143112221032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14311222703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1664075 + ... + 1672652.

It is an arithmetic number, because the mean of its divisors is an integer number (3578640780).

Almost surely, 214311222103 is an apocalyptic number.

14311222103 is a deficient number, since it is larger than the sum of its proper divisors (3341017).

14311222103 is an equidigital number, since it uses as much as digits as its factorization.

14311222103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3341016.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 14311222103 its reverse (30122211341), we get a palindrome (44433433444).

The spelling of 14311222103 in words is "fourteen billion, three hundred eleven million, two hundred twenty-two thousand, one hundred three".

Divisors: 1 4289 3336727 14311222103